Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.6 - Mole Relationships in Chemical Equations - Questions and Problems - Page 237: 7.48b

Answer

$\frac{ 4 \space moles \space HCl}{ 1 \space mole \space O_2}$ and $\frac{ 1 \space mole \space O_2}{ 4 \space moles \space HCl}$ $\frac{ 4 \space moles \space HCl}{ 2 \space moles \space Cl_2}$ and $\frac{ 2 \space moles \space Cl_2}{ 4 \space moles \space HCl}$ $\frac{ 4 \space moles \space HCl}{ 2 \space moles \space H_2O}$ and $\frac{ 2 \space moles \space H_2O}{ 4 \space moles \space HCl}$ $\frac{ 1 \space mole \space O_2}{ 2 \space moles \space Cl_2}$ and $\frac{ 2 \space moles \space Cl_2}{ 1 \space mole \space O_2}$ $\frac{ 1 \space mole \space O_2}{ 2 \space moles \space H_2O}$ and $\frac{ 2 \space moles \space H_2O}{ 1 \space mole \space O_2}$ $\frac{ 2 \space moles \space Cl_2}{ 2 \space moles \space H_2O}$ and $\frac{ 2 \space moles \space H_2O}{ 2 \space moles \space Cl_2}$

Work Step by Step

1. Use the balance coefficients to write the mole-mole equalities: 4 moles $HCl$ = 1 mole $O_2$ 4 moles $HCl$ = 2 moles $Cl_2$ 4 moles $HCl$ = 2 moles $H_2O$ 1 mole $O_2$ = 2 moles $Cl_2$ 1 mole $O_2$ = 2 moles $H_2O$ 2 moles $Cl_2$ = 2 moles $H_2O$ 2. Use these equalities to write the conversion factors: $\frac{ 4 \space moles \space HCl}{ 1 \space mole \space O_2}$ and $\frac{ 1 \space mole \space O_2}{ 4 \space moles \space HCl}$ $\frac{ 4 \space moles \space HCl}{ 2 \space moles \space Cl_2}$ and $\frac{ 2 \space moles \space Cl_2}{ 4 \space moles \space HCl}$ $\frac{ 4 \space moles \space HCl}{ 2 \space moles \space H_2O}$ and $\frac{ 2 \space moles \space H_2O}{ 4 \space moles \space HCl}$ $\frac{ 1 \space mole \space O_2}{ 2 \space moles \space Cl_2}$ and $\frac{ 2 \space moles \space Cl_2}{ 1 \space mole \space O_2}$ $\frac{ 1 \space mole \space O_2}{ 2 \space moles \space H_2O}$ and $\frac{ 2 \space moles \space H_2O}{ 1 \space mole \space O_2}$ $\frac{ 2 \space moles \space Cl_2}{ 2 \space moles \space H_2O}$ and $\frac{ 2 \space moles \space H_2O}{ 2 \space moles \space Cl_2}$
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