Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.6 - Mole Relationships in Chemical Equations - Questions and Problems - Page 237: 7.47b

Answer

$P \space and \space O_2: $ $\frac{4 \space moles \space P}{5 \space moles \space O_2}$ and $\frac{5 \space moles \space O_2}{4 \space moles \space P}$ $P \space and \space P_2O_5:$ $ \frac{4 \space moles \space P}{2 \space moles \space P_2O_5}$ and $\frac{2 \space moles \space P_2O_5}{4 \space moles \space P}$ $O_2 \space and \space P_2O_5:$ $\frac{5 \space mole \space O_2}{2 \space moles \space P_2O_5}$ and $\frac{2 \space moles \space P_2O_5}{5 \space mole \space O_2}$

Work Step by Step

1. Use the balance coefficients to write the mole-mole equalities: 4 moles $P$ = 5 moles $O_2$ 4 moles $P$ = 2 moles $P_2O_5$ 5 moles $O_2$ = 2 moles $P_2O_5$ 2. Use these equalities to write the conversion factors: $\frac{4 \space moles \space P}{5 \space moles \space O_2}$ and $\frac{5 \space moles \space O_2}{4 \space moles \space P}$ $\frac{4 \space moles \space P}{2 \space moles \space P_2O_5}$ and $\frac{2 \space moles \space P_2O_5}{4 \space moles \space P}$ $\frac{5 \space mole \space O_2}{2 \space moles \space P_2O_5}$ and $\frac{2 \space moles \space P_2O_5}{5 \space mole \space O_2}$
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