Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.6 - Mole Relationships in Chemical Equations - Questions and Problems - Page 237: 7.47a

Answer

$SO_2$ and $SO_3$: $\frac{2 \space moles \space SO_2}{2 \space moles \space SO_3}$ and $\frac{2 \space moles \space SO_3}{2 \space moles \space SO_2}$ $SO_2$ and $O_2$: $\frac{2 \space moles \space SO_2}{1 \space mole \space O_2}$ and $\frac{1 \space mole \space O_2}{2 \space moles \space SO_2}$ $O_2$ and $SO_3$: $\frac{1 \space mole \space O_2}{2 \space moles \space SO_3}$ and $\frac{2 \space moles \space SO_3}{1 \space mole \space O_2}$

Work Step by Step

1. Use the balance coefficients to write the mole-mole equalities: 2 moles $SO_2$ = 2 moles $SO_3$ 2 moles $SO_2$ = 1 mole $O_2$ 1 mole $O_2$ = 2 moles $SO_3$ 2. Use these equalities to write the conversion factors: $\frac{2 \space moles \space SO_2}{2 \space moles \space SO_3}$ and $\frac{2 \space moles \space SO_3}{2 \space moles \space SO_2}$ $\frac{2 \space moles \space SO_2}{1 \space mole \space O_2}$ and $\frac{1 \space mole \space O_2}{2 \space moles \space SO_2}$ $\frac{1 \space mole \space O_2}{2 \space moles \space SO_3}$ and $\frac{2 \space moles \space SO_3}{1 \space mole \space O_2}$
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