Lehninger Principles of Biochemistry 6th Edition

Published by W.H. Freeman
ISBN 10: 1-42923-414-8
ISBN 13: 978-1-42923-414-6

Chapter 2 - Water - Problems: 7

Answer

1.79 moles

Work Step by Step

For every acetylcholine, a hydrogen ion is released in the reaction which means [H] produced during the reaction = Acetylcholine concentration. [H] produced during reaction = [H] at the end- [H] at start of reaction [H] = $10^{-pH}$ [H] at start of reaction = $10^{-7.65}$ = $0.224 \times 10^{-7}$M [H] at the end of reaction = $10^{-6.87}$ = $1.35 \times 10^{-7}$M [H] produced during reaction = $(1.35 -0.224) \times10^{-7}$M =1.13M This is equal to acetylcholine concentration $1.13 \times10^{-7}$ moles in 1 liter In 15 mL or 0.0015 L, the number of moles = $1.13 \times10^{-7} \times 0.0015 L $ = $1.7 \times10^{-9}$ moles
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