Lehninger Principles of Biochemistry 6th Edition

Published by W.H. Freeman
ISBN 10: 1-42923-414-8
ISBN 13: 978-1-42923-414-6

Chapter 2 - Water - Problems: 3

Answer

a) $1.51\times 10^{-4}$M b) $3.02\times 10^{-7}$M c) $7.76\times 10^{-12}$M

Work Step by Step

pH = -$log_{10}[H]$ Rearranging, [H] = $10^{-pH}$ a) [H] = $10^{-3.82}$ =$1.51\times 10^{-4}$M b) [H] = $10^{-6.52}$ =$3.02\times 10^{-7}$M c) [H] = $10^{-11.11}$ = $7.76\times 10^{-12}$M
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