Lehninger Principles of Biochemistry 6th Edition

Published by W.H. Freeman
ISBN 10: 1-42923-414-8
ISBN 13: 978-1-42923-414-6

Chapter 2 - Water - Problems: 4

Answer

1.1

Work Step by Step

p[H] = -log[H] [H] is the molar concentration hydrogen ions [H] = moles of NaOH used to neutralize the gastric juice 7.2 ml of 0.1M NaOH solution contains = (7.2 $\div$ 1000) L $\times$ 0.1 moles/L = 0.00072 moles 10 mL of gastric juice neutralized by 0.00072 moles So 10 mL of gastric juice contains 0.00072 moles of Hhydrogen ions So 1 liter of gastric juice will contain 100 $\times$ 0.00072 moles = 0.072 moles [H] = 0.072 M pH = -log[0.072] = 1.1
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