Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 296: 19

Answer

$\dfrac{3}{5}$

Work Step by Step

$\sin{t} = \dfrac{1}{\csc{t}} = \dfrac{\sqrt{5}}{5}$ $\cos{t} = - \sqrt{1- \sin^2{t}} =- \sqrt{1-\left(\dfrac{-\sqrt{5}}{5}\right)^2}$ $\cos{t} = \dfrac{-2\sqrt{5}}{5}$ $\cos{2t} = 1 -2 \sin^2{t} = 1 -2 \left( \dfrac{\sqrt{5}}{5}\right)^2 = \dfrac{3}{5}$
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