Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 296: 20

Answer

$ - \dfrac{4}{5}$

Work Step by Step

$\sin{t} =\dfrac{\sqrt{5}}{5} \hspace{20pt} \cos{t} = \dfrac{-2\sqrt{5}}{5}$ $\sin{2t} = 2 \sin{t} \cos{t} = 2 \times \dfrac{\sqrt{5}}{5} \times \dfrac{-2\sqrt{5}}{5}$ $\sin{2t} = - \dfrac{4}{5}$
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