Answer
$\tan2y = \frac{2\tan y}{1-\tan^{2}y}$
Work Step by Step
By the double angle formula of tangent
$\tan2A = \frac{2\tan A}{1-\tan^{2}A}$
Replace "A" by "y" we get
$\tan2y = \frac{2\tan y}{1-\tan^{2}y}$
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