Answer
$\frac{\pi}{6}$
Work Step by Step
The range of $\arccos x$ is $0\leq\arccos x\leq\pi$.
The angle between 0 and $\pi$ whose cosine is $\frac{\sqrt 3}{2}$ is $\frac{\pi}{6}$.
$\arccos (\frac{\sqrt 3}{2})=\frac{\pi}{6}$.
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