Answer
$\frac{\pi}{4}$
Work Step by Step
$sin^{-1}(\frac{\sqrt 2}{2})=sin^{-1}(\frac{1}{\sqrt 2})$
Let $sin^{-1}(\frac{1}{\sqrt 2})=y$.
Then, sin y=$\frac{1}{\sqrt 2}$.
We know that $sin\frac{\pi}{4}=\frac{1}{\sqrt 2}$.
$⇒y= \frac{\pi}{4}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 261: 26
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