Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 261: 25

Answer

$-\frac{\pi}{6}$

Work Step by Step

Let $\sin(-\frac{1}{2})$= y. Then, sin y=$-\frac{1}{2}= -sin \frac{\pi}{6}=sin(-\frac{\pi}{6})$. This implies y= $-\frac{\pi}{6}$.
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