## Trigonometry 7th Edition

$\sin A = 0.800$ $\cos A = 0.600$ $\sin B = 0.600$ $\cos B =0.800$
Steps to Answer- We will use given data about triangle ABC and Pythagoras Theorem to solve for 'c'- We know that - $c^{2} =a^{2} + b^{2}$ ( Pythagoras Theorem) $c^{2} = (11.28)^{2} + (8.46)^{2}$ $c^{2} = 127.2384 +71.5716$ $c^{2} = 198.81$ therefore $c = \sqrt (198.81)$ = 14.10 Now we can write the required T-functions of A and B using $a=11.28$ , b = 8.46 and c = 14.10 $\sin A = \frac{a}{c} = \frac{11.28}{14.10}$ = $0.800$ $\cos A = \frac{b}{c} = \frac{8.46}{14.10}$ = $0.600$ $\sin B = \frac{b}{c} =\frac{8.46}{14.10}$ = $0.600$ $\cos B =\frac{a}{c} = \frac{11.28}{14.10}$ = $0.800$