Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.1 - Definition II: Right Triangle Trigonometry - 2.1 Problem Set: 61

Answer

$ \frac{1}{\sqrt 3}$

Work Step by Step

To find out exact value of $ \cot 60^{\circ}$, considering special triangle- $ 30^{\circ} - 60^{\circ} - 90^{\circ}$ $\cot 60^{\circ}$ = $\frac{side - adjacent - 60^{\circ}}{side - opposite - 60^{\circ}}$ $\cot 60^{\circ}$ = $ \frac{1}{\sqrt 3}$ =$ \frac{1}{\sqrt 3}$
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