Answer
1
Work Step by Step
To find out exact value of $ \cot 45^{\circ}$, considering special triangle- $ 45^{\circ} - 45^{\circ} - 90^{\circ}$
$\cot 45^{\circ}$ = $\frac{side - adjacent - 45^{\circ}}{side - opposite - 45^{\circ}}$
$\cot 45^{\circ}$ = $ \frac{1}{1}$
= 1
