Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Appendix A - Section A.2 - The Inverse of a Function - A.2 Problem Set - Page 496: 17

Answer

$f^{-1}(x) = 4x + 3$

Work Step by Step

$f(x) = \frac{x-3}{4}$ Let $f(x) = y$ $y = \frac{x-3}{4}$ $x = \frac{y-3}{4}$ $4x = y-3$ $4x + 3 = y$ $y = 4x + 3$ $f^{-1}(x) = 4x + 3$
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