Answer
$f^{-1}(x) = \frac{x+1}{3}$
Work Step by Step
$f(x) = 3x - 1$
Let $y = f(x)$
$y = 3x -1$
$x = 3y -1$
$x + 1 = 3y$
$y = \frac{x+1}{3}$
$f^{-1}(x) = \frac{x+1}{3}$
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