Answer
$f^{-1}(x) = \frac{3x-2}{x-1}$
Work Step by Step
$f(x) = \frac{x-2}{x-3}$
Let $f(x) = y$
$y = \frac{x-2}{x-3}$
$x = \frac{y-2}{y-3}$
$xy - 3x = y-2$
$xy -y = 3x -2$
$y(x-1) = 3x -2$
$y = \frac{3x-2}{x-1}$
$f^{-1}(x) = \frac{3x-2}{x-1}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Appendix A - Section A.2 - The Inverse of a Function - A.2 Problem Set - Page 496: 16
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