The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 14 - Binomial Distributions - Chapter 14 Exercises - Page 341: 14.26c

Answer

$\approx0.3729$

Work Step by Step

The formula for a binomial probability: $P(X=k)={n\choose k}p^k(1-p)^{n-k}$ Hence $P(X=2)={4\choose 2}(\frac{9}{19})^2(1-\frac{9}{19})^{4-2}\approx0.3729$
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