Answer
See below.
Work Step by Step
$P(X=1)={10\choose1}p^1(1-p)^{9}=10\cdot0.3\cdot0.7^9=0.121$
$P(X=2)={10\choose2}p^1(1-p)^{9}=45\cdot0.3^2\cdot0.7^8=0.2334$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 14 - Binomial Distributions - Chapter 14 Exercises - Page 341: 14.24b
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