Answer
$\approx0.3529$
Work Step by Step
Hence $P(X\lt2)=P(X=0)+P(X=1)={4\choose 0}p^0(1-p)^{4-0}+{4\choose 1}p^1(1-p)^{4-1}\approx0.0767+0.2762=0.3529$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 14 - Binomial Distributions - Chapter 14 Exercises - Page 341: 14.26d
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