Answer
See graph and explanations.
Work Step by Step
Step 1. Convert the equation into polar coordinates using $r^2=x^2+y^2, x=r\cdot cos\theta, y=r\cdot sin\theta$, we have $r^6=(r^2cos^2\theta-r^2sin^2\theta)^2$ which leads to $r^2=(cos^2\theta-sin^2\theta)^2=(cos2\theta)^2$, thus $r=\pm cos2\theta$
Step 2. As the graph of $r= cos2\theta$ is the same as $r=- cos2\theta$, we graph the first function as shown in the figure.