Answer
See graph and explanations.
Work Step by Step
Step 1. Convert the equation into polar form using $x^2+y^2=r^2, x=r\cdot cos\theta, y=r\cdot sin\theta$
we have $r^6=4r^2cos^2\theta r^2sin^2\theta$ which leads to $r^2=4sin^2\theta cos^2\theta=(sin2\theta)^2$, thus $r=\pm sin2\theta$
Step 2. As the graph of $r=sin2\theta$ is the same as $r=-sin2\theta$, we graph the first function as shown in the figure.
