Answer
$\approx$ 2.09 m/s
Work Step by Step
Suppose a point moves along a circle of radius $r$
and the ray from the center of the circle to the point
traverses $\theta$ radians in time $t$.
Let $ s=r\theta$ be the distance the point travels in time $t$.
The angular speed of the point is $\omega=\theta/t$.
The linear speed of the point is $v=s/t$.
$ v=r\omega$.
1 revolution = $ 2\pi$ radians.
----------
The speed of the current equals the linear speed of a point on the tip of a paddle.
$\theta$= $($100 rev$)\displaystyle \cdot\frac{2\pi\ rad}{1\ rev}=200\pi$ rad
t= 1 min = 60 s
$ v=\displaystyle \frac{s}{t}=\frac{r\theta}{t}=\frac{0.2\cdot 200\pi}{60}\approx$2.09439510239
$\approx$ 2.09 m/s
