Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.1 - Angle Measure - 6.1 Exercises - Page 481: 85

Answer

a. 282.7 rad/min b. 4524 in/min

Work Step by Step

Suppose a point moves along a circle of radius $r$ and the ray from the center of the circle to the point traverses $\theta$ radians in time $t$. Let $ s=r\theta$ be the distance the point travels in time $t$. The angular speed of the point is $\omega=\theta/t$. The linear speed of the point is $v=s/t$. $ v=r\omega$. ---------- 1 revolution = $ 2\pi$ radians. a. $\displaystyle \omega=\frac{45\cdot 2\pi}{1 \ min}=90\pi$ rad/min $\approx$282.7 rad/min b. $ v=r\omega=16\cdot 90\pi=1440\pi$ in/min $\approx 4524$ in/min
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