Answer
$7.886$
Work Step by Step
Using relation $pH=-log[H^{+}]$
This implies that $pH=-log[1.3 \times 10^{8}] \implies -\log 1.3 -\log 10^{-8}$
Thus, $pH=8 \log (10)-0.114=8(1)-0.114=7.886$
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