Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises - Page 390: 103

Answer

(a) $n(t)=1500e^{0.1515t}$ (b) $7940$

Work Step by Step

(a) We can obtain from the graph that $n_0=1500$ with the data point given on the graph, the function becomes $n(5)=1500e^{5r}=3200$, we obtain $r=ln(\frac{3200}{1500})/5=0.1515$ and the model function becomes $n(t)=1500e^{0.1515t}$ (b) Year 2020 corresponds to $t=2020-2009=11$, we have $n(11)=1500e^{0.1515\times11}\approx7940$
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