Answer
$10^{10.4}$
Work Step by Step
Here, we have $B_1=132 =10 \log \dfrac{I_1}{I_0}$
This gives: $I_1=I_0 10^{13.2}$ ...(1)
Now, $B_2=28 =10 \log \dfrac{I_2}{I_0}$
This gives: $I_2=I_0 10^{2.8}$ ...(2)
From equations (1) and (2), we have
$R=\dfrac{I_2}{I_1}=10^{13.2-2.8}=10^{10.4}$