Answer
1st term: 0; 2nd term: 3; 3rd term: 8; 4th term: 15; 100th term: 9999.
Work Step by Step
To find the nth term of sequence, plug in a number for n. So, for the first term, plug in 1 for n, for the second term, plug in 2 for n, and so on. In this case:
1. For the first term: $n^{2}-1$ = $1^{2}$ - 1 = 0.
2. Repeat this for the next three terms, plugging in 2, 3, and 4 for n and solving.
3. For the 100th term: $n^{2}-1$ = $100^{2} - 1 =10000-1= 9999$