Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 850: 11

Answer

1st term: 0; 2nd term: 2; 3rd term: 0; 4th term: 2; 100th term: 2

Work Step by Step

To find the nth term of sequence, plug in a number for n. So, for the first term, plug in 1 for n, for the second term, plug in 2 for n, and so on. In this case: 1. For the first term: 1 + $(-1)^{n}$ = $1 + (-1)^{1}$ = 0. 2. Repeat this pattern for the next three terms, plugging in 2, 3, and 4 for n and solving. 3. For the 100th term plug in 100 for n: 1 + $(-1)^{100}$ = 2.
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