Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises - Page 64: 80

$z=a+bi$ Therefore $z=\frac{}{.}(\frac{}{z})=a+bi$

$z=a+bi$ Find the conjugate of the complex number by changing the sign of their imaginary part: $\frac{}{z}=a-bi$ So $\frac{}{.}(\frac{}{z})=a+bi$ Therefore $z=\frac{}{.}(\frac{}{z})=a+bi$