Answer
$\dfrac{4+6i}{3i}=2-\dfrac{4}{3}i$
Work Step by Step
$\dfrac{4+6i}{3i}$
Multiply the fraction by $\dfrac{-3i}{-3i}$:
$\Big(\dfrac{4+6i}{3i}\Big)\Big(\dfrac{-3i}{-3i}\Big)=\dfrac{-12i-18i^{2}}{-9i^{2}}=...$
Substitute $i^{2}$ with $-1$:
$...=\dfrac{-12i-18(-1)}{-9(-1)}=\dfrac{-12i+18}{9}=\dfrac{18}{9}-\dfrac{12}{9}i=2-\dfrac{4}{3}i$
