Precalculus: Mathematics for Calculus, 7th Edition

a.) $\lt$ b.) $\gt$ c.) =
a.) 3 ? $\frac{7}{2}$ Rewrite the 3 $\frac{6}{2}$ ? $\frac{7}{2}$ $\frac{6}{2}$ is less than $\frac{7}{2}$ $\frac{6}{2}$ $\lt$ $\frac{7}{2}$ b.) -3 ? -$\frac{7}{2}$ Rewrite the -3 -$\frac{6}{2}$ ? -$\frac{7}{2}$ With negatives, the number closer to 0 is bigger than the one farther away from 0. $\frac{6}{2}$ $\gt$ $\frac{7}{2}$ c.) 3.5 ? $\frac{7}{2}$ Rewrite 3.5 (3.5 = 3$\frac{1}{2}$ or $\frac{7}{2}$) $\frac{7}{2}$ = $\frac{7}{2}$