## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises: 30

#### Answer

a.) $\frac{1}{15}$ b.) $\frac{35}{24}$

#### Work Step by Step

a.) $\frac{2}{3}$ - $\frac{3}{5}$ Least Common Denominator of 3 and 5 = 15 Therefore, $\frac{10}{15}$ - $\frac{9}{15}$ = $\frac{1}{15}$ b.) 1 + $\frac{5}{8}$ - $\frac{1}{6}$ Least Common Denominator of 1, 8, and 6 = 24 Therefore, $\frac{24}{24}$ + $\frac{15}{24}$ - $\frac{4}{24}$ = $\frac{35}{24}$

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