Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises: 28

Answer

3ab + 3ac - 6ad

Work Step by Step

Using the distributive property of real numbers (which states that when we multiply a number by a sum of two numbers we get the same result as we get if we multiply the number by each of the terms and then add the results), we multiply each of the elements in the parenthesis by 3a to write the expression without parentheses. (3a)(b + c - 2d) = ? (3a)(b + c - 2d) = (3a)(b) + (3a)(c) + (3a)(-2d) (3a)(b + c - 2d) = 3ab + 3ac - 6ad
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