Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Test - Page 137: 7

Answer

A) (2x+5)(2x-5) B)(2x-3)(x+4) C)(x+2)(x-2)(x+3) D) x(x+3)(x²-3x+9) E) 3$x^{-1/2}$[(x-2)(x-1)] F) xy[(x+2)(x-2)]

Work Step by Step

A) 4x²-25 (2x+5)(2x-5) B)2x²+5x-12 (2x-3)(x+4) C) x³-3x²-4x+12 (x³-3x²) -(4x+12) x²(x-3)-4(x-3) (x²-4)(x-3) (x+2)(x-2)(x+3) D) x⁴+27x x(x³+27) x(x+3)(x²-3x+9) E) 3$x^{3/2}$-9$x^{1/2}$+6$x^{-1/2}$ Take the common factor 3$x^{-1/2}$[x²-3x+2] 3$x^{-1/2}$[(x-2)(x-1)] F) x³y-4xy xy(x²-4) xy[(x+2)(x-2)]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.