Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Test - Page 137: 12

Answer

The dimensions of the parcel are $120$ ft in length and $50$ ft in width.

Work Step by Step

As we can see in the picture, there is a right triangle. So, we can use the Pythagorean Theorem $a^2+b^2=c^2$ to find $x$. $(x+70)^2+x^2=130^2$ $(x^2+70x+70x+4900)+x^2=16900$ $2x^2+140x+4900-16900=0$ $2x^2+140x-12000=0$ We can factor out a $2$ and then we can use the quadratic formula $2(x^2+70x-6000)=0$ $x^2+70x-6000=0$ $x={-70\pm\sqrt{(-70)^2-4(1)(-6000)}\over 2(1)}$ $x={-70\pm\sqrt{4900+24000}\over 2}$ $x={-70\pm\sqrt{28900}\over 2}$ We're only going to calculate the positive square root since negative values aren't used to measure distance. $x= {-70+170\over2}= {100\over 2}=50$ Therefore, the dimensions of the parcel are $70+50 = 120$ ft in length and $50$ ft in width
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.