Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Test - Page 137: 2

Answer

(a) $81$ (b) $-81$ (c) $\dfrac{1}{81}$ (d) $25$ (e) $\dfrac{9}{4}$ (f) $\dfrac{1}{8}$

Work Step by Step

(a) $(-3)^4=(-3)(-3)(-3)(-3)=81$ (b) $-3^4=-(3)(3)(3)(3)=-81$ (c) $3^{-4} = \dfrac{1}{3^4} = \dfrac{1}{81}$ (d) $\dfrac{5^{23}}{5^{21}}=5^{23-21}=5^2=25$ (e) $\left(\frac{2}{3}\right)^2=\dfrac{1}{\left(\frac{2}{3}\right)^2}=\dfrac{1}{\frac{4}{9}}=1 \cdot \dfrac{9}{4}=\dfrac{9}{4}$ (f) $16^{-\frac{3}{4}}=\dfrac{1}{16^{\frac{3}{4}}}=\dfrac{1}{\sqrt[4]{16^3}}=\dfrac{1}{\sqrt[4]{(2^4)^3}}=\dfrac{1}{2^3}=\dfrac{1}{8}$
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