Answer
$I10^{-\frac {d}{10}}$
Work Step by Step
$d=10\log \dfrac {I}{I_{0}}\Rightarrow \log \dfrac {I}{I_{0}}=\dfrac {d}{10}\Rightarrow \dfrac {I}{I_{0}}=10^{\frac {d}{10}}\Rightarrow I_{0}=I10^{-\frac {d}{10}}$
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