Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises: 59

Answer

$x_{1}=-\dfrac {4}{3};x_{2}=5$

Work Step by Step

$\log _{4}\left[ \left( 3x+1\right) \left( x-4\right) \right] =2\Rightarrow \left( 3x+1\right) \left( x-4\right) =4^{2}\Rightarrow 3x^{2}-11x-4=16$ $\Rightarrow 3x^{2}-11x-20=0\Rightarrow \left( 3x+4\right) \left( x-5\right) =0\Rightarrow $ $x_{1}=-\dfrac {4}{3};x_{2}=5$
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