Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises: 45

Answer

$\approx -2.487$

Work Step by Step

$6^{x-3}=3^{4x+1}\Rightarrow \dfrac {6^{x}}{6^{3}}=3^{4x}\times 3\Rightarrow \left( \dfrac {6}{3^{4}}\right) ^{x}=648\Rightarrow $ $x=\log _{\dfrac {6}{81}}648\approx -2.487$
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