Answer
$-\dfrac {2}{3}$
Work Step by Step
$32^{2x}=16^{x-1}\Rightarrow \left( 25\right) ^{2x}=\left( 2^{4}\right) ^{x-1}\Rightarrow 2^{10x}=2^{4x-4}\Rightarrow 10x=4x-4\Rightarrow 6x=-4\Rightarrow x=-\dfrac {2}{3}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 432: 80
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