Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 432: 75

Answer

$0$

Work Step by Step

$2^{3-2x}=8\Rightarrow 2^{3-2x}=2^{3}\Rightarrow 3-2x=3\Rightarrow x=\dfrac {3-3}{2}=0$
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