Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises: 82

Answer

$\dfrac {1}{2}$

Work Step by Step

$2^{6-3x}=8^{x+1}\Rightarrow 2^{6-3x}=\left( 2^{3}\right) ^{x+1}\Rightarrow 2^{6-3x}=2^{3x+3}\Rightarrow 6-3x=3x+3\Rightarrow 6x=3\Rightarrow x=\dfrac {1}{2}$
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