Answer
$16\ in$
Work Step by Step
Step 1. Assume $x\ (in)$ is the distance a spring stretches.
Step 2. Assume $F\ (lb)$ is the force applied.
Step 3. From the given conditions, we have $x=kF$ and $8=k(15)$, thus $k=\frac{8}{15}$
Step 4. For $F=30\ (lb)$ , we have $x=\frac{8}{15}(30)=16\ in$