Answer
$0.0444\ ohm$
Work Step by Step
Step 1. Assume $R\ (ohm)$ is the the resistance offered by a fixed length of wire of a given material.
Step 2. Assume $d\ (in)$ is the diameter of the wire.
Step 3. From the given conditions, we have $R=k/d^2$ and $0.4=k/(0.01)^2$, thus $k=4\times10^{-5}$
Step 4. For $d=0.03\ (in)$, we have $R=4\times10^{-5}/(0.03)^2\approx0.0444\ ohm$