Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.6 Variation - 3.6 Exercises - Page 389: 36

Answer

$40\ lb$

Work Step by Step

Step 1. Assume $w\ (lb)$ is the weight of an object. Step 2. Assume $d\ (mi)$ is its distance from the center of Earth. Step 3. From the given conditions, we have $w=k/d^2$ and $90=k/(8000)^2$, thus $k=90(8000)^2$ Step 4. For $d=12,000\ (mi)$, we have $w=90(8000)^2/(12000)^2=40\ lb$
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