Answer
$\sqrt {2x-6}$, domain $[3,\infty)$
Work Step by Step
Given $f(x)=\sqrt {x+1}, x\geq-1$ and $g(x)=2x-7$, we have
$(f\circ g)(x)=\sqrt {(2x-7)+1}=\sqrt {2x-6}$ and the domain is $2x-6\geq0\longrightarrow x\geq3$ or $[3,\infty)$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 2 - Graphs and Functions - Test - Page 302: 20
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