Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Test - Page 302: 11

Answer

(a) $y=-3x+9$ (b) $y=\frac{1}{3}x+\frac{7}{3}$

Work Step by Step

(a) If the line is parallel to $y=-3x+2$, it has a slope of $m_1=-3$, thus the equation is $y-3=-3(x-2)$ or $y=-3x+9$ (b) If the line is parallel to $y=-3x+2$, it has a slope of $m_2=-\frac{1}{-3}=\frac{1}{3}$, thus the equation is $y-3=\frac{1}{3}(x-2)$ or $y=\frac{1}{3}x+\frac{7}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.