Answer
$2\sqrt {x+1}-7$, domain $[-1,\infty)$
Work Step by Step
Given $f(x)=\sqrt {x+1}, x\geq-1$ and $g(x)=2x-7$, we have
$(g\circ f)(x)=2(\sqrt {x+1})-7=2\sqrt {x+1}-7$ and the domain is $ x\geq-1$ or $[-1,\infty)$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 2 - Graphs and Functions - Test - Page 302: 21
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